50=0.012x^2-0.543x+35.725

Solution for 50=0.012x^2-0.543x+35.725 equation:

50=0.012x^2-0.543x+35.725

We move all terms to the left:

50-(0.012x^2-0.543x+35.725)=0

We get rid of parentheses

-0.012x^2+0.543x-35.725+50=0

We add all the numbers together, and all the variables

-0.012x^2+0.543x+14.275=0

a = -0.012; b = 0.543; c = +14.275;
Δ = b2-4ac
Δ = 0.5432-4·(-0.012)·14.275
Δ = 0.980049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.543)-\sqrt{0.980049}}{2*-0.012}=\frac{-0.543-\sqrt{0.980049}}{-0.024}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.543)+\sqrt{0.980049}}{2*-0.012}=\frac{-0.543+\sqrt{0.980049}}{-0.024}
$